Question

find
the zesses of the Quadsasic
polynomial p(x)=4x²- 4x+1​

Answer 1

Answer:

4x² - 4x + 1

4x² - 2x - 2x + 1

2x(2x - 1) - 1(2x - 1)

(2x - 1)(2x - 1)

Step-by-step explanation:

HOPE IT WILL HELP YOU:-)

Answer 2

Answer:

(1/2)(1/2)

Step-by-step explanation:

|| ✰✰ ANSWER ✰✰ ||

Given , quadratic polynomial is 4x²-4x+1.

To Find The Number of Zeros Put The polynomial Equals to 0 First.

→ 4x² - 4x + 1 = 0

Now, Splitting The Middle Term , we get,

→ 4x² - 2x - 2x + 1 = 0

→ 2x(2x - 1) - 1(2x - 1) = 0

→ (2x - 1)(2x - 1) = 0

Putting Both Equal to Zero now, we get,

→ 2x - 1 = 0

→ 2x = 1

→ x = (1/2)

Hence, Both Zeros of Quadratic Equation Are (1/2).