Question

Find the10th term of ap 1 5 9 13....

Answer 1

Answer:

here

first term(a)=1

second term (a+d)=5

common difference(d)= a2-a1

=5-1

=4

10th term =a+9d

=1+9x4

=37 ans

Answer 2

Answer:

$\mathfrak{\large{\underline{\underline{Answer}}}} = 37$

Step-by-step explanation:

$\bold{ap = 1 + 5 + 9 + 13............} \\ \bold{first \: term = a = 1} \\ \bold{common \: difference = d = 4} \\ \bold{t10 \: terms = a + 9d} \\ \bold{1 + 9(4)} \\ \bold{37 = answer}$