Question

Find the11th term from the last term of the AP:10,7,4........-62. Also find the sum of last 11 terms

Answer 1

Your solution in this image.
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Answer 2

Since we have to find the 11 th term from last.... let's invert the AP i.e., new AP:-62,......4,7,10

a=-62
d=10-7=3
n=11
Therefore
$a_{11} = a + (11 - 1)d$
=-62+10×3
=-62+30
=-32
Now,
$s_{11} = \frac{n}{2} (2a - (n - 1)d)$
=11/2{2×(-32)-(11-1)×3}
=11/2{-64-10×3}
=11/2{-64-30}
=11/2(-94)
=11×(-47)
=-517