find the17th term form the end of the AP :1,6,11,16... ...211,216.
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If you observe the common difference(d) = 6 -1=5
or 11-6 =5
the nth term of a.p is given as = a + (n-1)d
the first term is a ,in this problem a = 1,n is the nth term
so 17th term = a + 16d = 1+ 16(5) = 81
or 11-6 =5
the nth term of a.p is given as = a + (n-1)d
the first term is a ,in this problem a = 1,n is the nth term
so 17th term = a + 16d = 1+ 16(5) = 81
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