Math, asked by adi4187, 1 year ago

find theboerimeter of rectangle whose length is 40 cm and digonal is 41cm

Answers

Answered by MOSFET01

I think perimeter

D=41 cm

L=40 cm

B=?

B²+L²=D²

B²+40²=41²

B²=41²-40²

B²=(41-40)(41+40)

B=√1(81)

B=9 cm

Perimeter= 2(l+b)

=2(40+9)

=2(49)

=98 cm²

Starbucks: L =40 cm
H=?

Diagonal =41cm
Diagonal and one side makes right angle triangle with height of the rectangle .......since diagonal will be hypotenuse

Let height be h
(40)²+(h)²=(41)²

(h)²=1681-1600
=81

So ,(h)²=81 and therefore h=9cm

Perimeter of rectangle=2(l+b)

MOSFET01: oh sorry mene wo pda nhi tha

Starbucks: =2(40+9) =2(49). =98 cm........hope u find it helpful

Starbucks: Koi baat nai yrrr

Answered by jinesh34

162 is a answer of your question

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