Question

find thee perimeter of a triangle whose sides are 4y-2z ,z-y ,2y+3z​

Answer 1

Answer:

perimeter =5y+2z

Step-by-step explanation:

sides

4y-2z

z-y

2y+3z

perimeter

= 4y-2z + z-y + 2y+3z

= (4y + 2y) -y  +( z+3z)-2z

= (6y-y)+ (4z-2z)

=5y+2z