Question

Find theeta if sin theta = cos theta = tan theta/ root 2

Answer 1

Answer:

ln(x+1)=ln(3x+1) - lnx

ln(x+1)=ln{(3x+1)/x}...taking antilogs

x+1=(3x+1)/x

x(x+1)=3x+1

x^2+x-3x-1=0

x^2-2x-1=0..using quadratic formula

x=1+sqrt.(2)....or......1-sqrt.(2)..but since logof negative number does not exist...1-sqrt.(2) cannot be a solution.

so...x=1+sqrt.2=2.4142 .