Find theFind the sum of first 11 terms of the AP: 1
15
,
1
12
,
1
10
… … … … … …. sum of first 11 terms of the AP: 1 15 , 1 12 , 1 10 … … … … … ….
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Answer:
a=115
d= -3
S11 = n/2[2a+(n-1)d]
=11/2[2×115+10×-3]
=11/2[230-30]
=11/2×200
=11×100
=1100
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