find their consecutive even number whose sum is 66
Answers
Answered by
7
Heya!
Here is yr answer.........
Suppose the even no. be x
Another even no. as x + 2 (consecutive)
=> x + x + 2 = 66
=> 2x + 2 = 66
=> 2x = 66 -2
=> 2x = 64
=> x =64/2
=> x = 32
=> x +2
=> 32 + 2
=>34
Therefore, the nos. are 32 and 34
Hope it hlpzzz....
Here is yr answer.........
Suppose the even no. be x
Another even no. as x + 2 (consecutive)
=> x + x + 2 = 66
=> 2x + 2 = 66
=> 2x = 66 -2
=> 2x = 64
=> x =64/2
=> x = 32
=> x +2
=> 32 + 2
=>34
Therefore, the nos. are 32 and 34
Hope it hlpzzz....
Answered by
1
hey ...here is your answer ... suppose two consecutive even no.'s are = x,,x+2
given
x+x+2=66
2x+2=66
2x= 64
x= 64/2
x= 32 ...
x+2= 32+2
= 34
so numbers are 32 nd 34 whose sum is 66 ..
I hope it helps you ...!!!
then pls.mark it as brainliest !!!
given
x+x+2=66
2x+2=66
2x= 64
x= 64/2
x= 32 ...
x+2= 32+2
= 34
so numbers are 32 nd 34 whose sum is 66 ..
I hope it helps you ...!!!
then pls.mark it as brainliest !!!
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