Math, asked by jiya168, 8 months ago

Find their present ages.
19. A father is 30 years older than his son. In 12 years, the man will be three times as old as his
son. Find their present ages.

Answers

Answered by Sauron
47

Answer:

The present age of Son = 3 years

The present age of Father = 33 years

Step-by-step explanation:

Let,

The present age of Son = x

The present age of Father = x + 30

After 12 years,

The age of Son = x + 12

The age of Father = x + 30 + 12

x + 42

Also,

The man will be three times as old as his

son

So,

⇒ 3 (x + 12) = x + 42

⇒ 3x + 36 = x + 42

⇒ 3x - x = 42 - 36

⇒ 2x = 6

⇒ x = 6 / 2

⇒ x = 3

The present age of Son = 3 years

Value of x + 30

⇒ 3 + 30

33

Therefore,

The present age of Son = 3 years

The present age of Father = 33 years

Verification :

12 years, the man will be three times as old as his son

⇒ The age of Son = 3 + 12 = 15

⇒ The age of Father = 33 + 12 = 45

⇒ 45 / 15 = 3

Answered by Anonymous
34

Let , The age of son be " x "

First Condition :

A father is 30 years older than his son

Thus ,

Father's age = x + 30 --- eq (i)

Second Condition :

After 12 years , the man will be three times as old as his son

Thus ,

x + 30 + 12 = 3(x + 12) --- [from eq (i)]

x + 42 = 3x + 36

2x = 6

x = 3

  \sf\therefore \underline{The  \: present \:  ages \:  of \:  father \:  and  \: son  \: are \:  33 \:  years  \: and \:  3 \:  years }

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