Question

find ther zeroes of the quadratic polynomial ײ+4×+3 and verify the relationship between the zeroes and the coefficients​

Answer 1

Answer:

Zeros = -3 , -1

Step-by-step explanation:

${x}^{2} + 4x + 3 \\ ({x}^{2} + 3x) + (x + 3) \\ (x + 1)(x + 3)$

Verification,

$\alpha + \beta = \frac{ - b}{a} \\ - 3 + - 1 = \frac{ - 4}{1} \\ - 4 = - 4 \\ \\ \alpha \beta = \frac{c}{a} \\ (- 3) \times ( - 1 )= \frac{3}{1} \\ 3 = 3$

Hence verified.

HOPE THIS WILL HELP YOU

Answer 2

Thnkx for question....

Solution....

x²+4x+3

x²+3x+x+3

x(x+3)+1(x+3)

(x+1)(x+3)

x+1=0 x+3=0

x=(-1) x=(-3)

zeroes are ...(-1),(-3)

Verification....

sum of zeroes = -coefficient of x

coefficient of x²

-1+(-3)= -4

1

-4=-4 .....

Product of zeroes = constant term

coefficient of x²

(-1)*(-3)= 3

1

3=3 .

Ans ...

Hence ..l.h.s =r.h.s ...

hope its helps u ...

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