Question

find ther zeroes of the quadratic polynomial ײ-5and verify the relationship between the zeroes and the coefficients​

Answer 1

Answer:

If we need to find the zeroes, the whole equation should be equal to zero

Step-by-step explanation:

$x {}^{2} - 5 = 0$

$x {}^{2} = 5$

$x = + \sqrt{5} \: or \: - \sqrt{5}$

These are the roots of the above equation

Answer 2

$\sqrt{5}$ or -$\sqrt{5}$

Step-by-step explanation:

=$p(x)=x^2-5\\x^2-5=0\\x^2=5\\x=\pm\sqrt{5} \\x=\sqrt{5} \\or\\-\sqrt{5} \\\\\alpha +\beta=\frac{-b}{a}=\frac{0}{1}=0\\\alpha\beta=\frac{c}{a}=\frac{-5}{1}\\x^2+(\alpha+\beta)x-\alpha\beta\\x^2+(0)x-5\\x^2-5\\\\Verified.$