Question

find there consecutive numbers whose sum is 108
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Answer 1

Answer:

Consider the three consecutive numbers,

x,x+1 and x+2

Now ,according to question,

x+(x+1)+(x+2)=108

3x+3=108

3x=105

x=35

Required three numbers are,

x=35,x+1=36 and x+2=37

Hence, this is the answer.

Answer 2

thanks for the free points

Step-by-step explanation:

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:)