Question

find theree numbers such that , the second is
twice the first the third is three times the
first their sum is 180.​

Answer 1

Answer :

• Three numbers are 30 , 60 and 90

Given :

• The second is twice the first , the third is three times
• Sum is 180

To find :

• Three numbers

Solution :

• Let the number be x ,y and z

Given that,

• The second is twice the first
• The third is three times so,

》y = 2x

》z = 3x

And also Given that , sum is 180 so,

• x + y + z = 180

where, y = 2x and z = 3x

》x + y + z = 180

》x + 2x + 3x = 180

》x + 5x = 180

》6x = 180

》x = 180/6

》x = 30

Now,

• x = 30
• y = 2x = 2(30) = 60
• z = 3x = 3(30) = 90

Hence , Three numbers are 30 , 60 and 90

Answer 2

★ Given :

• The second is twice the first the third is three times the first their sum is 180.

★ To find :

• The Three Numbers

★ Solution :

• In the question it is given That The second is twice the first the third is three times the first.

• So let he first Number will be x and The Second will be 2x and the third will be 3x

Let's Find out...!

⟹ x + 2x + 3x = 180

⟹ x + 5x = 180

⟹ 6x = 180

⟹ x = 180/6

⟹ x = 30.

Putting The values

✰ x = 30

✰ 2x = 2 × 30 = 60

✰ 3x = 3 × 30 = 90

∴ The numbers are 30,60 and 90

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