find these question please
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p(3)=3^3-2*3^2-5*3+6
= 27-18-15+6
=33-33
=0
so it is zero of polynomial p(x)
p(-2)= (-2)^3-2*-2^2-5*-2+6
=-8-8+10+6
=-16+16
=0
it is also
p(1)=1^3-2*1^2-5*1+6
=3-2-5+6
=9-7
=2
it is not zero of polynomial p(x)
= 27-18-15+6
=33-33
=0
so it is zero of polynomial p(x)
p(-2)= (-2)^3-2*-2^2-5*-2+6
=-8-8+10+6
=-16+16
=0
it is also
p(1)=1^3-2*1^2-5*1+6
=3-2-5+6
=9-7
=2
it is not zero of polynomial p(x)
AnmolAlam:
1^3 ka 3 nhi hota h
oh thanks it was by mistake
7-7 = 0
it is zero of polynomial p(x)
Don't worry
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