Question

find these questions please​

Answer 1

Refer the attachment ↑

Here, In The $\sf 1/4^{th}$ circle

BO = AO = Radius

AO = AP + OP

AO = 2 + 4.5

AO = 6.5 cm

Now, come to my drawn diagram,

Where, I have put OQ line

Now, Here ∠P = 90°, QO = Radius = 6.5 cm , OP = 4.5 (Given in question)

And we have to find PQ

So, Here We can use Pythagoras theorem

→ OQ² = PQ² + OP²

→ (6.5)² = PQ² + (4.5)²

→ 42.25 = PQ² + 20.25

→ 42.25 - 20.25 = PQ²

→ 22 = PQ²

→ PQ = √22 cm

Hence, Answer is √22 cm

I hope it helps you ❤️✔️