Math, asked by ashrafkhan6162, 10 months ago

Find theta for which sin theta = cos theta If theta is greater than 180 degree but less than 360 degree

Answers

Answered by pulakmath007
16

SOLUTION

TO DETERMINE

 \sf{The \:  value \:  of \:  \:  \theta } When

 \sf{ \sin \theta =  \cos \theta \: \:  \:   \: and \: \:  \:  {180}^{ \circ} <  \theta <  {360}^{ \circ}   } \:

EVALUATION

Here it is given that

 \sf{ \sin \theta =  \cos \theta \: \:  \:   \: and \: \:  \:  {180}^{ \circ} <  \theta <  {360}^{ \circ}   } \:

Now

 \sf{ \sin \theta =  \cos \theta \: \:  \:  \:  \:  gives} \:

 \tan \theta \:  = 1

  \implies \: \tan \theta \:  =  \tan \:  {45}^{ \circ}

  \implies \: \tan \theta \:  =  \tan \: ( {180}^{ \circ}   + {45}^{ \circ} )

  \implies \: \tan \theta \:  =  \tan \: {225}^{ \circ}

  \implies \:  \theta \:  =   \: {225}^{ \circ}

FINAL ANSWER

Hence the required value of   \theta is 225°

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Answered by prishad541
0

Step-by-step explanation:

Thevalueofθ When

\sf{ \sin \theta = \cos \theta \: \: \: \: and \: \: \: {180}^{ \circ} < \theta < {360}^{ \circ} } \:sinθ=cosθand180

<θ<360

EVALUATION

Here it is given that

\sf{ \sin \theta = \cos \theta \: \: \: \: and \: \: \: {180}^{ \circ} < \theta < {360}^{ \circ} } \:sinθ=cosθand180

<θ<360

Now

\sf{ \sin \theta = \cos \theta \: \: \: \: \: gives} \:sinθ=cosθgives

\tan \theta \: = 1tanθ=1

\implies \: \tan \theta \: = \tan \: {45}^{ \circ}⟹tanθ=tan45

\implies \: \tan \theta \: = \tan \: ( {180}^{ \circ} + {45}^{ \circ} )⟹tanθ=tan(180

+45

)

\implies \: \tan \theta \: = \tan \: {225}^{ \circ}⟹tanθ=tan225

\implies \: \theta \: = \: {225}^{ \circ}⟹θ=225

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