Find theta if 2 sin^2 theta - 5 sin theta +2 =0
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Answer:
sin 30
Step-by-step explanation:
Let sin theta=x
2x^2-5x+2=0
2x^2-4x-x+2=0
2x(x-2)-1(x-2)=0
(2x-1) (x-2) =0
x=1/2 x=2
sintheta=x
put the value of x=1/2
sintheta=1/2
theta=30
sint theta=30
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