Question

Find thevalue of ( 4^0+4^-1)*2^2​

Answer 1

4^0=1, 4^-1= 1/4^1, 2^2=4

Therefore,

(0+1/4)*4= 0*4 + 1/4*4  ( Multiply 4 to both the numbers )

= 0+4/4= 0+1

=1.

HOPE IT HELPS.

Answer 2

${\underline{\underline{\huge{\bf{\red{Solution}}}}}}$

$( {4}^{0} + {4}^{ - 1} ) \times {2}^{2} \\ \\ (= > {4}^{0} = 1 \\ = > {4}^{ - 1} = 0.25 \\ = > {2}^{2} = 4 )\\ \\ = (1 + 0.25) \times 4 \\ = 1.25 \times 4 = 5$

$\huge{\tt{\red{ThankYou}}}$

❤I hope it is the answer Pls make me as brainliest pls ❤