Question

find thevalue of k if x +3y-5=0 and kx-6y-10=0​

Answer 1

Answer:

the answer is

k= 2

x+3y-5=0

kx-6y-10=0

k=0

Answer 2

Step-by-step explanation:

given that

x+3y-5 = 0 ....(1)

kx-6y-10=0 .....(2)

on multiplying eq (1) by 2 we get

2(x+3y-5) = 2(0)

2x +6y -10 = 0 ..... (3)

Adding eq (2) & (3) we get

2x +6y -10 + (kx -6y-10) =0

2x +kx +6y - 6y -10-10 = 0

2x+kx -20 = 0

2x +kx =20

x(2 +k) = 20