Question

find thevalue ofa, for which P(a/3,2) is the modpoint of the line segment joining the oints Q (-5,4) and R(-1,0).​

Answer 1

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Answer:

$( \frac{ - 5 + ( - 1)}{2} . \frac{4 + 0}{2} ) = ( \frac{a}{3} .2) \\ \\ \frac{a}{3} = \frac{ - 6}{2} \\ \\ a = - 9$

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Answer 2

Answer:

a = -9

Step-by-step explanation:

Given midpoint of Q(-5,4) and R(-1,0) is P(a/3,2)

=> (-5 - 1/2, 4 + 0/2) = (a/3,2)

=> (-3,2) = (a/3,2)

Thus,

-3 = a/3

=> a = -9

Therefore, the value of a = -9

Hope it helps!