Question

Find thezero of root

Answer 1

Hey !!! ^_^


Here is your answer

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$\sqrt{ {3x}^{2} } + 10x + 7 \sqrt{3} = 0 \\ \\ \sqrt{ {3x}^{2} } + 7x + 3x + 7 \sqrt{3} = 0 \\ \\ x( \sqrt{3x} + 7) + \sqrt{3} ( \sqrt{3x} + 7) = 0 \\ \\ ( \sqrt{3x} + 7)(x + \sqrt{3} ) = 0 \\ \\ \sqrt{3x} + 7 = 0......or.....x + \sqrt{3} = 0 \\ \\ x = \frac{ - 7}{ \sqrt{3} } ....or \: ....x = - \sqrt{3}$


The zero of root is -7/√3 or -√3


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Answer 2

❤❤Here is your answer ✌ ✌

$\huge\boxed{\red{\bold{Answer}}}$

$\sqrt{3} x {}^{2} + 10x + 7 \sqrt{3} \ \\ \sqrt{3}x {}^{2} + 7x + 3x + 7 \sqrt{3} \\ x( \sqrt{3}x + 7) + \sqrt{3} ( \sqrt{3} x + 7) \\ (x + \sqrt{3} )( \sqrt{3} x + 7) \\ x = - \sqrt{3} \: \: or \: x = - 7/ { \sqrt{3} }$