Question

find this angle please fastly

Answer 1

i BAC+ABC+ACB=180
ACB=180-140
ACB=40degree

in triangle DEC
x=180-(100+40)
x=40°answar

Answer 2

In triangle ABC:
=A+B+C=180°
=50°+90°+x=180°
=140°+x=180°
=x=180°-140°
=x=40°
angle C=40°
In quadrilateral BCEF
=B+C+E+F=360°
=90+100+40+x=360
=230+x=360
=x=360-230
=x=130°
angle F=130°
triangle BDF
B+D+F=180
90+50+X=180
140+x=180
x=180-140
x=40°
F=40°