Question

find this.
fast it's ​

Answer 1

Answer:

Let

x−1

1

=X and

y−2

1

=Y

Hence, the given equations are reduced to:

5X+Y=2 ....(1)

6X−3Y=1 ....(2)

Multiplying (1) by 3, we get

15X+3Y=6 ....(3)

Adding (3) and (2), we get

21X=7

⇒X=

3

1

Substitute this value of X in (2), we get

6(

3

1

)−3Y=1

⇒2−3Y=1

⇒3Y=1

⇒Y=

3

1

Resubstitute the values of X and Y to get x and y,

X=

x−1

1

⇒

3

1

=

x−1

1

⇒x−1=3

⇒x=4

Y=

y−2

1

⇒

3

1

=

y−2

1

⇒y−2=3

⇒y=5

Hence, x=4,y=5 is the solution of the given simultaneous equations.

Answer 2

Answer:

5X+Y=2 ....(1)

6X−3Y=1 ....(2)

Multiplying (1) by 3, we get

15X+3Y=6 ....(3)

Adding (3) and (2), we get

21X=7

⇒X=

3

1

Substitute this value of X in (2), we get

6(

3

1

)−3Y=1

⇒2−3Y=1

⇒3Y=1

⇒Y=

3

1

Resubstitute the values of X and Y to get x and y,

X=

x−1

1

⇒

3

1

=

x−1

1

Step-by-step explanation: