Question

find this for me 22nd one all 3 bits

Answer 1

here the answer......

Answer 2

$x = 2 - \sqrt{3} \\ (a) \\ \frac{1}{x} = \frac{1}{2 - \sqrt{3}} \times \frac{2 + \sqrt{3}}{2 + \sqrt{3}} = \frac{2 + \sqrt{3} }{( {2})^{2} - ( \sqrt{3} ) ^{2} } = \frac{2 + \sqrt{3} }{4 - 3} = 2 + \sqrt{3} \\ (b) \: \: \: x + \frac{1}{x} = 2 - \sqrt{3} + 2 + \sqrt{3} = 4 \: \: \: \: \: \: \: .....(1) \\ (c) {x}^{2} + \frac{1}{ {x}^{2} } \\ (x + \frac{1}{x} )^{2} = {x}^{2} + \frac{1}{ {x}^{2} } + 2 \: \: \: \: \: \: \: \: = > \: (x + \frac{1}{x} = 4 \: \: \: from \: 1 )\\ (4) ^{2} = {x}^{2} + \frac{1}{ {x}^{2} } + 2 \\ 16 - 2 = {x}^{2} + \frac{1}{ {x}^{2} } \\ {x}^{2} + \frac{1}{ {x}^{2} } = 14$