Question

find this:
please explain this question briefly
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Answer 1

Answer:

Given:

Kinetic energy (initial) = 25 J

Mass = m

Initial Velocity = 5 m/s

Final vel. = 3 times the initial Velocity

To find:

New Kinetic energy

Calculation:

Initial case:

½ mv² = 25

=> ½ m (5)² = 25

=>½ m = 1

=> m = 2 kg ................(1)

Now, final Velocity = 3 times the initial Velocity

=> Final vel. (v") = 3 × 5 = 15 m/s

Final Kinetic energy

= ½ m (v")²

= ½ × 2 × (15)²

= 225 J

So the final answer is 225 Joules.

Answer 2

$\huge{\orange{\underline{\red{\mathscr{GIVEN:-}}}}}$

kinetic energy =25J.

initial =5m/s

object mass =m.

final velocity =3 time increased .

$\huge{\orange{\underline{\red{\mathscr{FIND:-}}}}}$

FINAL KINETIC ENERGY

$\huge{\orange {\underline{\red{\mathscr{ANSWER:-}}}}}$

1.initial case,

K. e=½mv²

25=½×m×(5)²

½×m=25-25

m=2kg.

THE FINAL VELOCITY IS INCREASED BY 3 TIME.

.°. final velocity (v') =3×5 =15m/s.

FINAL KINETIC ENERGY :-

K. e =½m(v') ²

K. e =1/2×2×(15)²

.°. K. e=225j.

$\huge{\orange{\underline{\red{\mathscr{THANKS.}}}}}$