Question

find this questio solution

Answer 1

{tan a/(sec a+1)}+{tan a/(sec a-1)}

= {(sin a/cos a)/((1/cos a)+1)}+{(sin a/cos a)/((1/cos a)-1)}

= {(sin a/cos a)/((1+cos a)/cos a)}+{(sin a/cos a)/((1-cos a)/cos a)}

= {sin a/(1+cos a)}+{sin a/(1-cos a)}

= {sin(1-cos a)+sina(1+cosa)}/{(1+cosa)(1-cosa)}

= 2 sina/1-cos²a

= 2 sina/1-(1-cos²a)

= 2sina/sin²a

= 2/sina

= 2cosec a

hope it helps you.......................

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