Math, asked by diyalucky9997852894, 8 months ago

find this quickly. I give you 20 points​

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Answered by biligiri
1

Answer:

15. x = (2-√5)/(2+√5) y = (2+√5)/(2-√5)

x = (2-√5)² / (2+√5)(2-√5)

x = (4 + 5 - 4√5) / (4 - 5)

x = (9 - 4√5) / -1

[ rationalise the denominator by multiplying both numerator and denominator by the conjugate of the denominator 2 - √5 ]

x = 4√5 - 9

x² = (4√5 - 9)²

=> 80 + 81 - 72√5

=> 161 - 72√5 ..................1

y = (2+√5) / (2-√5)

y = (2+√5)² / (2+√5)(2-√5)

[ rationalise the denominator by multiplying both numerator and denominator by the conjugate of the denominator 2 + √5 ]

y = (4 + 5 + 4√5) / (4 - 5)

y = (9 + 4√5) / -1

y = -9 - 4√5

y² = (-9 - 4√5)²

=> - ( 9 + 4√5)

=> - [ 81 + 80 + 72√5]

=> - 161 - 72√5....................2

1 - 2

=> 161 - 72√5 - (-161 - 72√5)

=> 161 - 72√5 + 161 + 72√5

=> 322

Answered by Khushibrainly
0

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