Question

find this squares by using the identities: (2/3m + 3/2n)^2 pls help..​

Answer 1

4/9m^2 + 12/6mn + 9/4n^2

OR

4/9m^2 + 2mn + 9/4n^2

Step-by-step explanation:

(a+b)^2 = a^2+2ab+b^2

Here, a=2/3m, b=3/2n

Then, (2/3m + 3/2n)^2

= (2/3m)^2 + 2×2/3m×3/2n + (3/2n)^2

=4/9m^2 + 12/6mn + 9/4n^2

=4/9m^2 + 2mn + 9/4n^2