Find this sum (3x+4y)square +(3x-4y)square.
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(3x+4y)^2 +(3x-4y)^2
=9x^2+16y^2+24xy+9x^2+16y^2-24xy
=18x^2+32y^2
=9x^2+16y^2+24xy+9x^2+16y^2-24xy
=18x^2+32y^2
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