Find those points on the x-axis, euch of which is at a distance of 5 units from the point (5,-3)
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Let the coordinates of the point be x,y
Since the point is on x axis, y= 0
using distance formula
√{(x-5)^2+(-3-0)^2}= 5
√{(x-5)^2+9}=5
By squaring both sides
x^2-10x+25+9=25
x^2-10x+9=0
(x-9)(x-1)=0
So coordinates are 9,0 and 1,0
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