Question

Find those points on x-axis, each of which is at a distance of 5 units
from the point A(5,-3).
[CBSE 2011]​

Answer 1

Answer:

Let the pointbeA=(x

1

,y

1

)=(p,0)[sinceitisontheX−axis]&atadistanceof

d=5unitsfromthepointB=(x

2

,y

2

)=(5,−4).Now

thedistancebetweentwopoints(x

1

,y

1

)and(x

2

,y

2

)isd=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

∴

(5−p)

2

+(−4−0)

2

=5

⟹p

2

−10p+16=0

⟹(p−8)(p−2)=0

∴p=8or2

Sothepointsare(8,0)&(2,0)