Question

Find those three consecutive terms of ap whose sum is 39 and their product of first two terms is 117

Answer 1

Answer:

9,13,17

Step-by-step explanation:

let that consecutive terms be a,b and c

a+b+c=39

according to AP

b+x. +b+. b -x =39

3b=39

b=13

now

a*b =117

a=117/13=9

c=13+4(x=4)

=17