Question

find thr value of a and b in the following equation √3+√2 by√3-√2=a+b√6​

Answer 1

Answer:

(√3+√2)/(√3-√2)

=(√3+√2)^2/(√3+√2)(√3-√2)

=(3+2+2.√3.√2)/(√3^2-√2^2)

=(5+2√6)/(3-2)

=5+2√6

so, here a=5 , b=2