Find thre consecutive odd number whose sum is 147
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Let (x+1) (x+3) (x+5) be the three consecutive odd no. Then
(x+1) +(x+3)+(x+5)=147
3x+9=147
X=46 put the value of x uh will get 147
(x+1) +(x+3)+(x+5)=147
3x+9=147
X=46 put the value of x uh will get 147
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