Find thre least number which when divided by 6 15 & 18 leaves remainder 5 in each case
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Find the L.C.M of 6, 15, and 18
6 = 2 × 3
15 = 3 × 5
18 = 2 × 3 × 3
L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5
L.C.M (6, 15 and 18) = 90
Therefore, the required number = 90+5 = 95
As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.
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