find three conceive even interior whose sum is 108 find the number
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Answered by
1
let three consecutive numbers be x,x+1,x+2
sum=108
x+x+1+x+2=108
3x+3=108
3x=108-3=105
x=105/3=35
x+1=36
x+2=37
sum=108
x+x+1+x+2=108
3x+3=108
3x=108-3=105
x=105/3=35
x+1=36
x+2=37
Answered by
0
let three consecutive no.s be x, x+1,x+2
a.t.q.
x+x+1+x+2=108
3x+ 3=108
3x=108÷3
3x=36
x= 36÷3
x=18
a.t.q.
x+x+1+x+2=108
3x+ 3=108
3x=108÷3
3x=36
x= 36÷3
x=18
Anonymous:
this is wrong
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