find three concicutive odd number whose sum is 45
Answers
Answered by
0
Answer:
13,15,17
Step-by-step explanation:
let 1st odd no. be x
then 2nd odd no. = x+2
3rd odd no. = x+4
so... (x)+(x+4)+(x+2)=45
3x+6=45
3(x+2)=45
x+2=15
x=13
Answered by
2
Answer :-
13 , 15 and 17 .
Given :-
Sum = 45
Solution :-
Let three consecutive positive integer be x+2 , x +4 , x + 6
Their sum is 45
A/Q
x + 2 + x + 4 + x + 6 = 45
→ 3x + 12 = 45
→3x = 45 - 12
→3x = 33
→ x = 11
hence, first number is x + 2
= 11 + 2
= 13
Second number is x + 4
= 11 + 4
= 15
Third number is x + 6
= 11 + 6
= 17
Verification :-
If we add this three odd number we get 45 as result.
→13 + 15 + 17 = 45
→ 45 = 45
hence, L. H. S = R. H. S
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