Question

Find three conescutive whole numbers whose sum is more than 45 but less than 54

Answer 1

Answer:

15,16,17 or 16,17,18

Step-by-step explanation:

Let the 3 consecutive numbers be x, x + 1 and x + 2

Their sum = x + x + 1 + x + 2 = 3x + 3

3x + 3  > 45 and 3x + 3 < 54

Therefore 3x > 42 or x > 14

          and 3x < 51 or x < 17

Therefore there are 2 possible sets, 15,16,17 or 16,17,18

Answer 2

Answer:

Let’s take the three consecutive whole numbers to be x, x + 1 and x + 2.

The given conditions are,

45 < x + (x + 1) + (x + 2) and x + (x + 1) + (x + 2) < 54

45 < 3x + 3 and 3x + 3 < 54

45 – 3 < 3x and 3x < 54 – 3

42 < 3x and 3x < 51

14 < x and x < 17

So, x = 15, 16

Now, if x = 15

The other numbers are 16, 17.

If x = 16,

The other number are 17, 18.

Therefore, the three consecutive whole number are 15, 16, 17 or 16, 17, 18.