Question

find three consective numbers such that the sum of the first and second is 15 more than the third​

Answer 1

Step-by-step explanation:

Let the first consecutive number = x,

Second consecutive number = x + 1

and Third consecutive number = x + 2

According to the condition,

x + x + 1 = 15 + x + 2

⇒ 2x + 1 = 17 +x

⇒ 2x -x = 17 – 1

⇒ x= 16

∴ The first consecutive number = 16

Second consecutive number =16+1 = 17

Third consecutive number =16 + 2=18

Answer 2

Answer:

16 , 17 & 18

Step-by-step explanation:

Let the numbers be x,x+1,x+2

The sum of first 2 numbers = 15 + the third number

So,x + x + 1 = x + 2 + 15

    2x + 1 = x + 17

    x = 16

So, the numbers are 16,17,18

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