Question

find three consective postive even integers whose sum is 90​

Answer 1

Answer:

Step-by-step explanation:

Let n , n+2, n+4 be the three positive integers whose sum is 90

Then n+n+2+n+4=90

3n+6=90

3(n+2)=90

n+2=90/3

n+2=30

n=30-2=28

The required three integers are:

n=28

n+2=30

n+4=32

Answer 2

Answer:

Step-by-step explanation: let the smallest no. Be x since they are consecutive even integers . ..

Similarly others are x ,( x+2) , (x+4)

There for sum of three no. Is 90

x+(x+2) + ( x+4)= 90

3x +6 = 90

3x= 84

X=84/3=28

•°• no. Are 28 , 30 ,32

Product would be 28×30×32=26880