Question

find three consective terms in A. P whose sum is 9 and the product of their cubes is 3375​

Answer 1

Step-by-step explanation:

Let the 3 consecutive no.s in AP be a-d, a, a+d

Sum = a-d +a+ a+ d

= 3a

Therefore, 3a =9, a=3

[(a-d)*a*(a+d)]^3 = 3375

(a^2 - d^2)*a = 15

9-d^2* 3 = 15

9 -d^2=5

d^2=9-5

d= +- 2

Three no.s are 1,3,5