Question

find three consecutive even integers such that the sum of the smallest number and twice the middle number is 20 more than the larger number.

Answer 1

Answer:

idk

Step-by-step explanation:

sub to mr beast road to50mil

Answer 2

Answer:

Let x, x+2 & x+4 be the 3 integers.

x+2(x+2)=(x+4)+20

x+2x+4=x+4+20

3x+4=x+24

3x-x=24-4

2x=20

x=20/1

x=10 ans. for the smallest integer.

10+2=12 for the middle integer.

10+4=14 ans. for the largest integer.