Question

Find three consecutive even integers such that the sum of the first and the last numbers exceeds the second number by 10

Answer 1

Hey There!


Here, Let the three consecutive even integers be n, n+2, n+4



Now, Sum of first and last numbers exceeds the second by 10.

That is: [First + Last] - Second = 10

So, (n+n+4) - (n+2) = 10
So, 2n+4-n-2 = 10
So, n+2 = 10

So, n=8

So, n+2 = 10

So, n+4 = 12



Thus, the three numbers are 8, 10 and 12.

Hope it helps
Purva
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