Math, asked by fahmeedanaaz24oct200, 8 days ago

Find three consecutive even integers such that the sum of twice the first integer , four more than the second and seven less than the third integer is 27. . Find the integers.​

Answers

Answered by Anushka1503
0

Answer:

15

Step-by-step explanation:

Let the three consecutive odd integers be x, x+2, x+4

Three times the first of three consecutive odd integers is 3 more than twice the third.

∴ 3x=2(x+4)+3

∴ x=11

Hence, the third integer is 11+4=15.

Answered by karanghodake428
1

Answer:

3,1,7 is the right answer

it's a King

Similar questions