Find three consecutive even integers such that the sum of twice the first integer , four more than the second and seven less than the third integer is 27. . Find the integers.
Answers
Answered by
0
Answer:
15
Step-by-step explanation:
Let the three consecutive odd integers be x, x+2, x+4
Three times the first of three consecutive odd integers is 3 more than twice the third.
∴ 3x=2(x+4)+3
∴ x=11
Hence, the third integer is 11+4=15.
Answered by
1
Answer:
3,1,7 is the right answer
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