Find three consecutive even integers such that the sum of twice the first integer , four more than the second and seven less than the third integer is 27. . Find the integers.
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Answer:
6, 8,and 10
Step-by-step explanation:
let the first even integer be 2x
second even integer will be 2x+2
third even integer will be 2x+4
condition given
the sum of twice the first integer , four more than the second and seven less than the third integer is 27.
so,
twice the first integer =2×2x = 4x
four more than the second integer= 2x+2+4= 2x+6
seven less than the third integer= 2x+4-7= 2x-3
sum of all integer = 27
Therefore,
first even integer be 2x=2×3= 6
second even integer will be 2x+2= 2×3+2= 8
third even integer will be 2x+4= 2×3+4=10
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