Find three consecutive even integers such that their sum decreased by twice the second integer is 54.
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Let x = smallest of the three even integers
Then, the other two are x+2 and x+4
2[x + (x+4)] = 2(x+2) + 44
2(2x+4) = 2x + 48
4x+8 = 2x+48
2x = 40
x = 20
ANSWER: The numbers are 20, 22, and 24
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