Question

Find three consecutive even integers such that their sum is 50 more than the largest integer

Answer 1

Answer:

24,26,28

Step-by-step explanation:

Integers = x,y,z an x<y<z

Equation = x+y+z = z+50

As x, y and z are consecutive even integers. We can take y as (x+2) and z as (x+4).

x+(x+2)+(x+4)=(x+4)+50

3x+6=x+54

3x-x+6=54

3x-x=54-6

2x=48

x=24

Integers = 24,26,28