Question

find three consecutive even integers whose sum is 108.​

Answer 1

Answer:

let term x,x+1,x+2,x+3

now x+x+2+x+3=108

3x+5=108

x=103/3

Answer 2

[tex]\huge\red{HELLO\:MATE}[/tex]

Let the first number be x.

Then second number x+2.

Then third number = x +4.

Atq, x + x + 2 +x+4= 108.

=> 3x + 6= 108.

=>3x = 108 - 6

=> 3x = 102

Therefore x = 34

So,

first number = x = 34.

second number = x+2 = 34+2=36.

Third number=x+4 = 34+4 =38.