Question

find three consecutive even integers whose sum is 108

Answer 1

Let the first integer be x then second =x+2, third =x+4

x+x+2+x+4=108
3x+6=108
3x=102
x=102/3=34

34,36,38

Answer 2

The three consecutive even integers are 34, 36, and 38 whose sum is 108.

Given,

The Sum of three consecutive even integers is 108.

To Find,

Three consecutive even integers.

Solutions,

Let the three consecutive even integers be n, n+2, and n+4.

According to the question,

n + n+2 + n+4 = 108

⇒ 3n + 6 = 108

⇒ 3(n + 2) = 108

⇒ n + 2 = 108/3

⇒ n + 2 = 36

⇒ n = 36 - 2

⇒ n = 34

Therefore, n, n+2, n+4 = 34, 36, 38

Hence, the three consecutive even integers are 34, 36, and 38 whose sum is 108.

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